If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. The Cambridge Examiner - Сторінка 1211884Повний перегляд - Докладніше про цю книгу
| Woolwich roy. military acad - 1864 - 588 стор.
...Chelsea be arranged, under the restriction that the tvco vowels e shall never stand together 1 10. If a straight line be divided into two equal parts,...of section is equal to the square on half the line. Hence show that a square is the greatest rectangle of given perimeter. 11. Describe a circle about... | |
| Euclides - 1864 - 448 стор.
...2am + at'. Hence by adding these equals, .-. (a + m)* + (o — m)' = 2aa + 2m'. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts is equal to twice the square of half the number itself,... | |
| Euclides - 1864 - 262 стор.
...— 2am + m'. Hence by adding these equals, .'. (a + m)' + (a - m)* = 2az + 2m*. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts is equal to twice the square of half the number itself,... | |
| Euclides - 1865 - 402 стор.
...by the parts. Cor. The parallelograms about the diameter of a square are likewise squares. Prop. 5. If a straight line be divided into two equal parts,...contained by the unequal parts, together with the square of the line between the noinls of section, is equal to the square of half the line. Cor. The difference... | |
| Robert Potts - 1865 - 528 стор.
...1am + m*, Hence by adding these equals, .'. (a + m)t + (a — m)« = 2o* + 2m«. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts, is equal to twice the square of half the number itself,... | |
| James McDowell - 1866 - 124 стор.
...f- = tan - - - 1. 1 + tan|a \4 2/ If a + ft + 7 = ^, prove that cos a + cos /3 + cos 7 If an angle be divided into two equal parts and also into two unequal parts, the rectangle of the sines of the unequal parts, together with the square of the sine of the angle between the dividing... | |
| Euclid, Isaac Todhunter - 1867 - 424 стор.
...manifest, that parallellograms about the diameter of a square are likewise squares. PROPOSITION 5. THEOREM. If a straight line be divided into two equal parts...into two unequal parts, the rectangle contained by iht unequal parts, together with the square on the line between the points of section, is equal to... | |
| Euclid, Isaac Todhunter - 1867 - 426 стор.
...about the diameter of a square are likewise squares. PROPOSITION 5. THEOREM. If a straight line 1ie divided into two equal parts and also into two unequal parts, the rectangle contained l)y the unequal parts, together with the square on the line between the points of section, is equal... | |
| 1868 - 344 стор.
...explain how rectangular areas are represented by the product of two numerical symbols. SECTION VI. 1. If a straight line be divided into two equal parts, and also into two unequal parts, the rectal gle contained by the unequal parts, together with the square of the line between the points... | |
| Robert Potts - 1868 - 434 стор.
...= a' — m*, to each of these equals add m* ; .'. (a + m) (a — m) + m' = a*. That is, if a number be divided into two equal parts, and also into two unequal parts, the product of the unequal parts together with the square of half their difference, is equal to the square... | |
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