Arithmetic of Electricity: A Practical Treatise on Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, and Involving Only Ordinary Arithmetic ...N.W. Henley Publishing Company, 1909 - 162 стор. |
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Сторінка 118
... .02 is 20,000,000 . Dividing the former product by the latter gives 23.562 volts , Answer . The coefficient of self - induction or , as it is more frequently termed , the inductance of a coil , is 118 ARITHMETIC OF ELECTRICITY .
... .02 is 20,000,000 . Dividing the former product by the latter gives 23.562 volts , Answer . The coefficient of self - induction or , as it is more frequently termed , the inductance of a coil , is 118 ARITHMETIC OF ELECTRICITY .
Сторінка 119
... inductance of a coil , is meas- ured by the number of volts of counter E. M. F. when the current changes at the rate of one ampere per second . ( Atkinson . ) The unit of inductance is the henry . Rule 84. The inductance of a coil is ...
... inductance of a coil , is meas- ured by the number of volts of counter E. M. F. when the current changes at the rate of one ampere per second . ( Atkinson . ) The unit of inductance is the henry . Rule 84. The inductance of a coil is ...
Сторінка 120
... inductance . EXAMPLE . Find the inductive resistance of a circuit whose frequency is 60 cycles per second and the inductance is .05 henry . Solution : 6.2832 X 60 X .05 = 18.8496 ohms . Ans . The time constant of an inductive circuit is ...
... inductance . EXAMPLE . Find the inductive resistance of a circuit whose frequency is 60 cycles per second and the inductance is .05 henry . Solution : 6.2832 X 60 X .05 = 18.8496 ohms . Ans . The time constant of an inductive circuit is ...
Сторінка 124
... inductance and the capacity , to have their effects neutralized , and when this adjustment is effected the current will be con- trolled by the volts and ohmic resistance the same as if it were a direct current circuit . The impedance is ...
... inductance and the capacity , to have their effects neutralized , and when this adjustment is effected the current will be con- trolled by the volts and ohmic resistance the same as if it were a direct current circuit . The impedance is ...
Сторінка 125
... inductance and a capacity in series , calculate both the inductive resistance and the capacity re- sistance ; their difference will be the impedance . EXAMPLE . Find the current produced by an alternating E. M. F. of 40 volts on a ...
... inductance and a capacity in series , calculate both the inductive resistance and the capacity re- sistance ; their difference will be the impedance . EXAMPLE . Find the current produced by an alternating E. M. F. of 40 volts on a ...
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50 cents 50 ohms 50 volts air gaps alternating current ampere turns ance appliances armature core battery C. G. S. units calculated calories capacity cells in parallel cells in series circular mils coefficient of leakage coil conductance conductor copper coulombs cross-sectional area cycles per second difference of potential distance divided drop dynamo efficiency electromotive force energy engines EXAMPLE expressed external circuit factors farad field resistance fractions given gives gram heat developed horse power horse-power inductance internal resistance joules kilogram-meter lamps in parallel leads length lines of force lines per square magnet core magnetic circuit meter microfarad microhms mils in diameter motor multiplied number of cells number of turns Ohm's law ohms resistance permeability permeance proportion ratio of conversion reciprocal reduced reluctance Rule 55 Rules 30 sectional area shunt Solution specific resistance square centimeter square inch tion turns of wire voltage weight wrought iron
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