Arithmetic of Electricity: A Practical Treatise on Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, and Involving Only Ordinary Arithmetic ...N.W. Henley Publishing Company, 1909 - 162 стор. |
З цієї книги
Результати 1-5 із 8
Сторінка 60
... coulombs divided by the acceleration of gravitation ( 9.81 meters ) . This gives the result in kilogram - meters . ( 7.23 foot pounds . ) EXAMPLE . E. C. t W = 9.81 A current of 20 amperes is maintained in a circuit by an E. M. F. of 20 ...
... coulombs divided by the acceleration of gravitation ( 9.81 meters ) . This gives the result in kilogram - meters . ( 7.23 foot pounds . ) EXAMPLE . E. C. t W = 9.81 A current of 20 amperes is maintained in a circuit by an E. M. F. of 20 ...
Сторінка 79
... coulombs is determined . Rule 62. To calculate the metal or other element lib- erated by a given current per given time proceed as fol- lows : Calculate the resistance . Determine the counter- electromotive force of the solution by Rule ...
... coulombs is determined . Rule 62. To calculate the metal or other element lib- erated by a given current per given time proceed as fol- lows : Calculate the resistance . Determine the counter- electromotive force of the solution by Rule ...
Сторінка 80
... coulombs , and for copper deposited .00033 × 35,280 11.64 grams . - In many cases one electrode is made of the mater- ial to be deposited and being connected to the car- bon end of the battery or generator is dissolved as fast as the ...
... coulombs , and for copper deposited .00033 × 35,280 11.64 grams . - In many cases one electrode is made of the mater- ial to be deposited and being connected to the car- bon end of the battery or generator is dissolved as fast as the ...
Сторінка 81
... dissolve . Calculate the deposit . Solution : Current 3.8 ÷ ( .24 + .023 ) = amperes = = = 14.4 51,840 coulombs per hour .00033 X 51,840 17.10 grams of copper . = CHAPTER IX . ELECTRO - MAGNETS , DYNAMOS AND MOTORS BATTERIES . 81.
... dissolve . Calculate the deposit . Solution : Current 3.8 ÷ ( .24 + .023 ) = amperes = = = 14.4 51,840 coulombs per hour .00033 X 51,840 17.10 grams of copper . = CHAPTER IX . ELECTRO - MAGNETS , DYNAMOS AND MOTORS BATTERIES . 81.
Сторінка 121
... coulombs ( i . e . , ampere - seconds ) ; the E. M. F. in volts , and the capacity in farads . Condensers in practical use have , however , so small a capacity that it is usually stated in microfarads and the quantity in CHAPTER XII ...
... coulombs ( i . e . , ampere - seconds ) ; the E. M. F. in volts , and the capacity in farads . Condensers in practical use have , however , so small a capacity that it is usually stated in microfarads and the quantity in CHAPTER XII ...
Інші видання - Показати все
Загальні терміни та фрази
50 cents 50 ohms 50 volts air gaps alternating current ampere turns ance appliances armature core battery C. G. S. units calculated calories capacity cells in parallel cells in series circular mils coefficient of leakage coil conductance conductor copper coulombs cross-sectional area cycles per second difference of potential distance divided drop dynamo efficiency electromotive force energy engines EXAMPLE expressed external circuit factors farad field resistance fractions given gives gram heat developed horse power horse-power inductance internal resistance joules kilogram-meter lamps in parallel leads length lines of force lines per square magnet core magnetic circuit meter microfarad microhms mils in diameter motor multiplied number of cells number of turns Ohm's law ohms resistance permeability permeance proportion ratio of conversion reciprocal reduced reluctance Rule 55 Rules 30 sectional area shunt Solution specific resistance square centimeter square inch tion turns of wire voltage weight wrought iron
Популярні уривки
Сторінка 50 - This loss as previously explained, is equal to the square of the current multiplied by the resistance. The...
Сторінка 13 - The strength of the current is equal to the electro-motive force divided by the resistance...
Сторінка 57 - Specific Heat. The specific heat of a substance is the ratio of the heat required to raise the temperature of unit weight of the substance 1 deg.