Arithmetic of Electricity: A Practical Treatise on Electrical Calculations of All Kinds Reduced to a Series of Rules, All of the Simplest Forms, and Involving Only Ordinary Arithmetic ...N.W. Henley Publishing Company, 1909 - 162 стор. |
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Сторінка 7
... Ampere - Turns for Given Magnetic Flux . - Magnetic Circuit Calculations . - Leakage of Lines of Force . - Example of Calculation of a Mag- netic Circuit . - Dynamo Armatures . - Voltage and Capacity of Armatures .-- Drum Type Closed ...
... Ampere - Turns for Given Magnetic Flux . - Magnetic Circuit Calculations . - Leakage of Lines of Force . - Example of Calculation of a Mag- netic Circuit . - Dynamo Armatures . - Voltage and Capacity of Armatures .-- Drum Type Closed ...
Сторінка 84
... amperes of current and to the number of turns the conductor makes around it . Its intensity is often given in ampere - turns . Magnetization always implies a circuit . As far as known , magnetic lines of force cannot exist without a ...
... amperes of current and to the number of turns the conductor makes around it . Its intensity is often given in ampere - turns . Magnetization always implies a circuit . As far as known , magnetic lines of force cannot exist without a ...
Сторінка 87
... ampere turns = 440,000 x .0047 = 2068 . - The same number of lines are to be forced through a bar 25.80 square centimeters area and 25.40 centimeters long . Calculate the ampere turns . = ELECTRO - MAGNETS , DYNAMOS AND MOTORS . 87.
... ampere turns = 440,000 x .0047 = 2068 . - The same number of lines are to be forced through a bar 25.80 square centimeters area and 25.40 centimeters long . Calculate the ampere turns . = ELECTRO - MAGNETS , DYNAMOS AND MOTORS . 87.
Сторінка 88
... ampere turns . = 440,000 25.80 Solution : 440,000 lines through 25.80 sq . cent . 17,054 through 1 sq . cent . , for which the permeability = 161. The reluctance therefore , ( b ) = 25.40 ÷ ( 1.2566 × 25.80 × 161 ) = .0048 . The ampere ...
... ampere turns . = 440,000 25.80 Solution : 440,000 lines through 25.80 sq . cent . 17,054 through 1 sq . cent . , for which the permeability = 161. The reluctance therefore , ( b ) = 25.40 ÷ ( 1.2566 × 25.80 × 161 ) = .0048 . The ampere ...
Сторінка 92
... ampere turns ( the analogue of volts of E. M. F. ) . The preceding leakage rules cover the case of parallel leg magnets . For others a slight change is requisite in the leakage calcula- tions , but in practice an average can generally ...
... ampere turns ( the analogue of volts of E. M. F. ) . The preceding leakage rules cover the case of parallel leg magnets . For others a slight change is requisite in the leakage calcula- tions , but in practice an average can generally ...
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Загальні терміни та фрази
50 cents 50 ohms 50 volts air gaps alternating current ampere turns ance appliances armature core battery C. G. S. units calculated calories capacity cells in parallel cells in series circular mils coefficient of leakage coil conductance conductor copper coulombs cross-sectional area cycles per second difference of potential distance divided drop dynamo efficiency electromotive force energy engines EXAMPLE expressed external circuit factors farad field resistance fractions given gives gram heat developed horse power horse-power inductance internal resistance joules kilogram-meter lamps in parallel leads length lines of force lines per square magnet core magnetic circuit meter microfarad microhms mils in diameter motor multiplied number of cells number of turns Ohm's law ohms resistance permeability permeance proportion ratio of conversion reciprocal reduced reluctance Rule 55 Rules 30 sectional area shunt Solution specific resistance square centimeter square inch tion turns of wire voltage weight wrought iron
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