Machine-shop Arithmetic: Shows how All Shop Problems are Worked Out and "why"N.W. Henley Publishing Company, 1907 |
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Результати 1-5 із 15
Сторінка 10
... necessary , taking care to count only those used , when placing the decimals in the answer . Division being the reverse of multipli- cation it seems almost self - evident that pointing off should also be reversed . If the reasons given ...
... necessary , taking care to count only those used , when placing the decimals in the answer . Division being the reverse of multipli- cation it seems almost self - evident that pointing off should also be reversed . If the reasons given ...
Сторінка 17
... root figure . Annexing this to the trial divisor gives 22 for the true divisor and multiplying by 2 gives 44 , coming out even in this case . are necessary . Sometimes several trials Chapter III . Conventional Rule for Cube Root . ( 17.
... root figure . Annexing this to the trial divisor gives 22 for the true divisor and multiplying by 2 gives 44 , coming out even in this case . are necessary . Sometimes several trials Chapter III . Conventional Rule for Cube Root . ( 17.
Сторінка 23
... necessary between letters , as A and B in this case , and is often omitted , C = A B meaning that C product of A B. In some English works multiplication is denoted by a period where we usually place the decimal point , their decimal ...
... necessary between letters , as A and B in this case , and is often omitted , C = A B meaning that C product of A B. In some English works multiplication is denoted by a period where we usually place the decimal point , their decimal ...
Сторінка 29
... necessary . Before going on with useful shop for- mula , let us take a " horrible example " and see how it is solved , which will per- haps clear up some of the mysteries better than the simple formulas . Taking a2 + b2 - c2 ) 2 b A ...
... necessary . Before going on with useful shop for- mula , let us take a " horrible example " and see how it is solved , which will per- haps clear up some of the mysteries better than the simple formulas . Taking a2 + b2 - c2 ) 2 b A ...
Сторінка 31
... necessary to make the required weight . Dividing this by the length , 15 inches , we have 51.28 square inches as the area of the ring whose outer diameter is 10 inches . Then we can say 51.28 ( A ) = . 7854 × ( 100 — ɗ2 ) and trans ...
... necessary to make the required weight . Dividing this by the length , 15 inches , we have 51.28 square inches as the area of the ring whose outer diameter is 10 inches . Then we can say 51.28 ( A ) = . 7854 × ( 100 — ɗ2 ) and trans ...
Загальні терміни та фрази
50 cents answer arithmetic assumed number bolt calculation Centimeters Chapter ciphers circumference COLVIN cube root cubic inches cutter decimal places decimal point Diam dividend dividing divisor drill driving electrical equal EQUIVALENTS evidently feet per minute figure formula four threads fractions fully illustrated Gallons gas engines gives handy hole Huron stone hypothenuse inches in diameter Kilograms last change gear lathe lathe center leading screw Liquefaction of Gases Liters locomotive machine mechanic metal Meters metric system Millimeters milling cutter Milling Machine Modern multi number of teeth number of threads pebbles pipe pounds practical treatise principle pulley quantity ratio result revolutions per minute rule screw cutting shaft shows side speed spindle square inches square root steam steel stud that takes subtract taps tens number threads desired threads in leading threads per inch tion triangle twice units weight wheel whole numbers
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Сторінка 113 - The metre, which is assumed to be one ten-millionth part of the distance from the equator to the pole, is, in fact, 39J inches, or 39.37 inches, in length.