Machine-shop Arithmetic: Shows how All Shop Problems are Worked Out and "why"N.W. Henley Publishing Company, 1907 |
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Результати 1-5 із 10
Сторінка 27
... holes , 3 and 5 inches re- spectively , are as 3 × 3 = 9 and 5 × 5 = 25 , or as 9 is to 25 , or if one will pass 9 cubic feet of air or water per second , the other will pass 25 . Having found the area of a shaft , we have only to ...
... holes , 3 and 5 inches re- spectively , are as 3 × 3 = 9 and 5 × 5 = 25 , or as 9 is to 25 , or if one will pass 9 cubic feet of air or water per second , the other will pass 25 . Having found the area of a shaft , we have only to ...
Сторінка 36
... hole 3 inches in diameter ; what will be the dimension of the flat sides ? The diagonal is what reams the holes and this must be 3 inches , so we have c = √ a2 + b2 and c = 3 inches . To find a we have a = √2—62 or knowing that a and ...
... hole 3 inches in diameter ; what will be the dimension of the flat sides ? The diagonal is what reams the holes and this must be 3 inches , so we have c = √ a2 + b2 and c = 3 inches . To find a we have a = √2—62 or knowing that a and ...
Сторінка 39
... the outer diameter of the shaft 10 inches and the whole which is eccentric to the shaft , 5 inches in diameter ; what is the area of the one sided ring ? Of course the area is exactly the same as though the hole was in the centre of the 39.
... the outer diameter of the shaft 10 inches and the whole which is eccentric to the shaft , 5 inches in diameter ; what is the area of the one sided ring ? Of course the area is exactly the same as though the hole was in the centre of the 39.
Сторінка 40
... hole was in the centre of the shaft , and we use the formula : Area .7854 ( D2 - d2 ) as before . A little study ... hole for stud 3 inches , and having 6 holes for tools , each 2 inches in diameter . First calculate for volume as though ...
... hole was in the centre of the shaft , and we use the formula : Area .7854 ( D2 - d2 ) as before . A little study ... hole for stud 3 inches , and having 6 holes for tools , each 2 inches in diameter . First calculate for volume as though ...
Сторінка 41
... holes . Central hole of 3 inches diameter by 6 inches long . 3x3x.7854-7.0686 and 7.0686 x 6 = 42.4116 or 42.41 + cubic inches . Taking holes next , we find that a the turret is 20 inches in diameter and cen- tral hole 3 inches , the ...
... holes . Central hole of 3 inches diameter by 6 inches long . 3x3x.7854-7.0686 and 7.0686 x 6 = 42.4116 or 42.41 + cubic inches . Taking holes next , we find that a the turret is 20 inches in diameter and cen- tral hole 3 inches , the ...
Загальні терміни та фрази
50 cents answer arithmetic assumed number bolt calculation Centimeters Chapter ciphers circumference COLVIN cube root cubic inches cutter decimal places decimal point Diam dividend dividing divisor drill driving electrical equal EQUIVALENTS evidently feet per minute figure formula four threads fractions fully illustrated Gallons gas engines gives handy hole Huron stone hypothenuse inches in diameter Kilograms last change gear lathe lathe center leading screw Liquefaction of Gases Liters locomotive machine mechanic metal Meters metric system Millimeters milling cutter Milling Machine Modern multi number of teeth number of threads pebbles pipe pounds practical treatise principle pulley quantity ratio result revolutions per minute rule screw cutting shaft shows side speed spindle square inches square root steam steel stud that takes subtract taps tens number threads desired threads in leading threads per inch tion triangle twice units weight wheel whole numbers
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Сторінка 113 - The metre, which is assumed to be one ten-millionth part of the distance from the equator to the pole, is, in fact, 39J inches, or 39.37 inches, in length.