 | William Nicholson - 1809 - 722 стор.
...add the sqnare of its height ; multiply the sum by the height, and the product by .r>'236.' Or, 2<Uy, From three times the diameter of the sphere, subtract twice the height of the fribtnim ; multiply the remaintier by the square of the height, and the product by .5236. SEGUIERIA,... | |
 | Charles Hutton - 1815 - 686 стор.
...the square of its height ; multiply the sum by the height, and the product by '5236. Or, 2dly, From 3 times the diameter of the sphere, subtract twice the height of the frustum ; multiply the remainder by the square of the height, and the product by '5236. That is, in... | |
 | Thomas Keith - 1817 - 306 стор.
...tUe globe is the .greatest. PROBLEM XIII. Tojlnd the Solidity of the Segment of a Sphere. RULE 1 *. From three times the diameter of the sphere, subtract twice the height of the segment ; multiply * Demonstrauon. Let A cm represent a triangular pyramid, whose tide m A is infinitely small. The sphere... | |
 | William Hawney - 1820 - 336 стор.
...the theorems become d2+fAa ; xA.x .785* ix Ax. 7854. To find the Solidity of the Segment of a Sphere. From three times the diameter of the sphere subtract twice the height of the segment ; multiply the remainder by the square of the height, and that product by .5236, and the last product will be... | |
 | William Nicholson - 1821 - 382 стор.
...add the square of its height ; multiply the sum by the height, and the pioduct by .52J6. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIER1A,... | |
 | James Mitchell - 1823 - 666 стор.
...add tile square of its height; multiply the sum by the height, and the product by -5236. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum ; multiply the remainder by the square of the height, and the product by -5236. That is, in... | |
 | Anthony Nesbit - 1824 - 476 стор.
...this sum multiplied by the height, and the product again by .5236, will give the solidity. RULE II. From three times the diameter of the sphere subtract twice the height of the segment; multiply the remainder by the square of the height, and that pro-i duct by .5236 for the solidity, Note l. The... | |
 | John Bonnycastle - 1829 - 256 стор.
...and this sum multiplied by the height, and the product again by .5236, will give the solidity. Or, From three times the diameter of the sphere subtract twice the height of the segment, multiply by the square of the height, and that .product by .5236 ; the last product will be the solidity. EXAMPLES.... | |
 | J. M. Scribner - 1844 - 130 стор.
...and the height of the segment be known, the solidity may be easily found by the following Rule. — From three times the diameter of the sphere, subtract twice the height of the segment ; then multiply the remainder by the square of the height and the product by the decimal .5236. Ex.... | |
 | Scottish school-book assoc - 1845 - 444 стор.
...inches. PROBLEM X. by the height, and the product again by -5236, will give the solidity. EULB II. From three times the diameter of the sphere subtract twice the height of the segment ; multiply the remainder by the square of the height and by -5236. NOTE. For the demonstration of the above Rules... | |
| |
To three times the square of the radius of its base add the square of its height; multiply this sum by the height and the product by 0.5236. 
