The Elements of Natural Philosophy1853 |
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Elements of Natural Philosophy ... Section I. Mechanics William Holmes Chambers BARTLETT Повний перегляд - 1850 |
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angle of resistance Axiom axis axle balance beam called centre of gravity coefficient of friction Corollary denote described direction distance draw drawn equal and opposite equilibrium Euclid exerts fall feet find the resultant fixed force of friction force which presses forces acting fore formula fulcrum given Hence horizontal plane inch inclined plane law of motion length magnitude manner measure mechanical middle point move parallel forces parallelogram parallelogram of forces particles perpendicular point of sliding portion pound weights pressure principle PROBLEM Prop proportion PROPOSITION pull pulley radius reaction represent respectively right angles rigid body round scale-pan screw shown in fig string substance suppose supposition surface suspended tendency tension three forces tie-beam tion triangle upwards velocity vertical weight wheel Wherefore
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Сторінка 189 - ... the sum of the moments of the forces which tend to turn the body in one direction must be equal to the sum of the moments of those which tend to turn it in the opposite direction about the same axis.
Сторінка 225 - ... the number by which the diameter of a circle must be multiplied to get the length of the circumference.
Сторінка 226 - ... this line. It will be useful to observe that the centre of gravity of a triangle coincides with the centre of gravity of three equal weights placed at the angular points of the triangle. For, to find the centre of gravity of three equal weights placed at the points A, B, C, respectively (see fig. 1, Plate IV.), we join CB and bisect it in E; then E is the centre of gravity of the weights at C and B. Suppose these weights collected at E, then join AE, and divide AE in...
Сторінка 327 - The amount of friction is independent of the extent of the surfaces in contact. 3. The...
Сторінка 349 - B The 25-pound force is the resultant of two forces acting at right angles to each other. The resultant can be represented as the hypotenuse of a right triangle, with one side representing the 15-pound force and the other side the unknown (x) force. Then, applying the Pythagorean Theorem, (hypotenuse)2 = (side)2 + (side)2 (25)2 = (15)2 625 = 225 + x2 400 = x2 20 = x 1 4.
Сторінка 263 - W2 are not greatly different from each other, the arithmetical mean of the two weights is usually sufficient unless extreme accuracy is required. 50. Sensibility of the Balance. The delicacy of the balance is determined by its sensibility. This depends upon a number of considerations and...
Сторінка 420 - similia;' never potency. Who ever heard of a homoeopath explaining to a patient that the pellet he is swallowing contains less than the millionth part of the millionth part of the millionth part of a grain of common salt or of flint ! Who ever heard of one of this school informing a patient with incipient hydrophobia, that the medicine given him to smell, not to swallow, and which will cure him, contains the decillionth part of a grain of chalk ; or rather that it contains no chalk at all, but...
Сторінка 333 - If a body be placed upon a rough inclined plane, and be on the point of sliding down the plane under the action of its weight and the reactions of the plane only, the angle of inclination of the plane to the horizon is equal to the angle of friction. Let...
Сторінка 75 - This must be done in such a way as not to interfere with the expansion of the chest through the window anteriorly.
Сторінка 30 - It is clear from the method of the two previous articles that, if in a uniform body we can find a point G such that the body can be divided into pairs of particles balancing about it, then G must be the centre of gravity • of .the body. The centre of gravity of a uniform circle, or uniform sphere, is therefore its centre. It is also clear that if we can divide a lamina into strips, the...