Examples of the Processes of the Differential and Integral CalculusJ. and J.J. Deighton, 1846 - 529 стор. |
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Сторінка 104
... perpendicular to OM ; find when the difference between OP and OM is the greatest . Let POM = α , ОР - ф - Ө ф , ом ; then we have = = a maximum ; while , by Napier's rules for the solution of right - angled spherical triangles , tan ...
... perpendicular to OM ; find when the difference between OP and OM is the greatest . Let POM = α , ОР - ф - Ө ф , ом ; then we have = = a maximum ; while , by Napier's rules for the solution of right - angled spherical triangles , tan ...
Сторінка 105
... perpendicular to the upper surface of the prism . Join OM , RP , SQ intersecting each other in N. Then it is easy to see that MN NO and consequently SO = QN , and as the triangles POR , PMR are equal , the pyramids PSRO and PMRQ are ...
... perpendicular to the upper surface of the prism . Join OM , RP , SQ intersecting each other in N. Then it is easy to see that MN NO and consequently SO = QN , and as the triangles POR , PMR are equal , the pyramids PSRO and PMRQ are ...
Сторінка 120
... perpendicular to both the lines ( 1 ) and ( 2 ) , since we have I ( mn ' - m'n ) + and l ' ( mn ' - m ' n ) + m ( n l ' — n ' l ) + n ( Im ' — l'm ) = 0 , - m ' ( n l ' — n'l ) + n ' ( I'm ' − l ' m ) = 0 , which are the conditions of ...
... perpendicular to both the lines ( 1 ) and ( 2 ) , since we have I ( mn ' - m'n ) + and l ' ( mn ' - m ' n ) + m ( n l ' — n ' l ) + n ( Im ' — l'm ) = 0 , - m ' ( n l ' — n'l ) + n ' ( I'm ' − l ' m ) = 0 , which are the conditions of ...
Сторінка 126
... perpendicular to AB , and let AN , ON = y ; also let AON = 0 , BON = 4 , CON = √ . Then u2 = x2 + y2 , v2 = ( c − x ) 2 + y2 , w2 = ( b cos A − x ) 2 + ( b sin △ − y ) 2 . - In order that u + v + w may be a minimum , we must have ...
... perpendicular to AB , and let AN , ON = y ; also let AON = 0 , BON = 4 , CON = √ . Then u2 = x2 + y2 , v2 = ( c − x ) 2 + y2 , w2 = ( b cos A − x ) 2 + ( b sin △ − y ) 2 . - In order that u + v + w may be a minimum , we must have ...
Сторінка 130
... perpendicular CDE , of indefinite length . Take a point 0 in CA produced such that AO = AC ; then if the rectangular ruler NLM , of which the leg LM is equal to the diameter of the circle , be moved so that the leg NL always slides ...
... perpendicular CDE , of indefinite length . Take a point 0 in CA produced such that AO = AC ; then if the rectangular ruler NLM , of which the leg LM is equal to the diameter of the circle , be moved so that the leg NL always slides ...
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