 | James Joseph Sylvester, James Whitbread Lee Glaisher - 1862 - 410 стор.
...similitude of X and 2:" secondly, by observing that the triangle FGHm&j be constructed from 2 and Д (the triangle formed by joining the middle points of the sides of ABC) just as ÂED is constructed from X and ABC, whence it follows that these triangles are similar;... | |
 | Robert Henry Wright - 1865 - 174 стор.
...useful to find a form for the interior angles of the three following systems of triangles : (1) Of the triangle formed by joining the middle points of the sides of the triangle of reference. (2) Of the triangle formed by joining the feet of the perpendiculars let... | |
 | Isaac Todhunter - 1867 - 372 стор.
...gravity of a wire bent into a triangular shape coincides with the centre of the circle inscribed in the triangle formed by joining the middle points of the sides of the original triangle. 7. If the centre of gravity of a triangle be equidistant from two angular points... | |
 | Isaac Todhunter - 1867 - 368 стор.
...gravity of a wire bent into a triangular shape coincides with the centre of the circle inscribed in the triangle formed by joining the middle points of the sides of the original triangle. 7. If the centre of gravity of a triangle be equidistant from two angular points... | |
 | James McDowell - 1867 - 120 стор.
...Shew that the centre of gravity of the perimeter coincides with the centre of the circle inscribed in the triangle formed by joining the middle points of the sides of the given triangle. Let ABC be the given triangle, D, E, F, the middle A points of its sides. The weights... | |
 | James Maurice Wilson - 1868 - 150 стор.
...middle points of the sides of a triangle is parallel to the base, and is equal to half the base. 6. The triangle formed by joining the middle points of the sides of a triangle is similar to the original triangle, and has one fourth of its area. 7. The lines that join... | |
 | Dublin city, univ - 1871 - 366 стор.
...4. Prove that the centre of gravity of a triangular frame is the centre of the circle inscribed in the triangle formed by joining the middle points of the sides of the frame. $. Required, in Ibs., the force .F, which, acting freely for one minute upon the mass of... | |
 | Sir George Greenhill - 1876 - 318 стор.
...completely represented, three by the sides of a triangle taken in order, and three by the sides of the triangle formed by joining the middle points of the sides of the original triangle, prove that they will be in equilibrium if the parallel forces act in the same... | |
 | Euclides - 1877 - 58 стор.
...sides^£, AC of an isosceles triangle ABO, equal parts AD, AE are cut off ; shew that BE is equal to CD. 8. The triangle formed by joining the middle points of the sides of an equilateral triangle is also equilateral. 9. ABCD is a quadrilateral such that AB is equal to BC,... | |
 | Euclides - 1883 - 176 стор.
...contained by the sum and difference of the parts is equal to the rectangle contained by the parts. 3. The triangle formed by joining the middle points of the sides of a triangle is a fourth of the whole triangle. 4. The lines joining the middle points of the sides of... | |
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... the sides of the triangle formed by joining the middle points of the sides of the original triangle... 
