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" The angles at the base of an isosceles triangle are equal to each other ; and if the equal sides be produced, the angles on the other side of the base shall be equal. "
Solutions to the questions of the general examination at Easter, 1848 ... - Сторінка 230
автори: J. Goodall, W. Hammond - 1848
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The elements of plane trigonometry

John Charles Snowball - 1837 - 322 стор.
...С); Again, since each of the angles A, B, С is less than тг, .-. A + B + С<3тг. 22. The angles at the base of an isosceles triangle are equal to each other. (Fig. Art. 28.) Suppose ABC to be an isosceles triangle, having AB = AC, and therefore ¿ AOB = z AOC....
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A complete treatise on practical land-surveying

Thomas Holliday - 1838 - 404 стор.
...the shortest straight line that can be drawn from the vertical angle to the base. Note 1. The angles at the base of an isosceles triangle are equal to each other. 2. A line drawn from the middle of the base of an isosceles triangle to the opposite angle is perpendicular...
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The British Annals of Education for ...: Being The ..., Томи 1&nbsp;–&nbsp;2

1844 - 688 стор.
...A. 1 . Define a circle and the centre of a circle. What do you understand by an angle in a segment ? 2. The angles at the base of an isosceles triangle are equal to one another ; and if tbe equal sides be produced, the angles upon the other side of the base shall...
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Euclid's Elements of geometry [book 1-6, 11,12] with explanatory notes ...

Euclides - 1845 - 546 стор.
...of the one equal to two sides, &c. Which was to be demonstrated. PROPOSITION V. THEOREM. The angles at the base of an isosceles triangle are equal to each other; and if the equal sides be produced, the angles on the other side of the base shall be equal. Let ABC...
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Minutes ...: Correspondence, Financial Statements, Etc., and Reports ..., Том 2

Great Britain. Committee on Education - 1848 - 606 стор.
...each Section is to be answered.) Section 1. 1. Define я circle, a triangle, an isosceles triangle, and an equilateral triangle. Prove that the angles,...point out the equivalence of the two assumptions. Section 2. 1. Make a triangle of which the sides shall be equal to three given straight lines. State...
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Report of the Committee of Council on Education (England and Wales ..., Випуск 2

Great Britain. Council on Education - 1848 - 596 стор.
...each Section is to be answered.) Section 1. 1. Define a circle, a triangle, an isosceles triangle, and an equilateral triangle. Prove that the angles,...point out the equivalence of the two assumptions. .Section 2. 1. Make a triangle of which the sides shall be equal to three given straight lines. Slate...
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Minutes of the Committee of Council on Education: with Appendices, Том 1

Great Britain. Committee on Education - 1848 - 514 стор.
...a straight line perpendicular to a given straight line from a given point within it. 3. The angles at the base of an isosceles triangle are equal to each other, and if tho equal sides be produced the angles on the other side of the base shall be equal. Section...
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The English Journal of Education, Том 2

1848 - 542 стор.
...it. — See " Bell's Euclid," prop. i. book i. ; or " Tate's Geometry," &c. page 21. 3. The angles at the base of an isosceles triangle are equal to each other, and if the equal sides be produced, the angles on the other side of the base shall be equal. — See...
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Report of the Committee of Council on Education (England and Wales ..., Випуск 1

Great Britain. Council on Education - 1848 - 532 стор.
...straight line from a given point within it. 1. Define a plane superficies, and a circle. 3. The angles at the base of an isosceles triangle are equal to each other, and if the equal sides be produced the angles on the other side of the base shall be equal. Section...
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General Report on Public Instruction in the Bengal Presidency

1863 - 830 стор.
...; prove that AC and BD bisect each other. Under wht circumstances will AC equal BD ? 8. The angles at the base of an isosceles triangle are equal to each other. Give Euclid's proof of this proposition. How might it be proved if you were permitted to bisect an...
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