Examples of the Processes of the Differential and Integral CalculusJ. and J.J. Deighton, 1846 - 529 стор. |
З цієї книги
Результати 1-5 із 34
Сторінка 104
... perpendicular to OM ; find when the difference between OP and OM is the greatest . Let POM = a , OP = 4 , OM = 0 ; then we have - Ꮎ $ = a maximum ; while , by Napier's rules for the solution of right - angled spherical triangles , tan ...
... perpendicular to OM ; find when the difference between OP and OM is the greatest . Let POM = a , OP = 4 , OM = 0 ; then we have - Ꮎ $ = a maximum ; while , by Napier's rules for the solution of right - angled spherical triangles , tan ...
Сторінка 105
... perpendicular to the upper surface of the prism . Join OM , RP , SQ intersecting each other in N. Then it is easy to see that MN = NO and consequently _SO = QN , and as the triangles POR , PMR are equal , the pyramids PSRO and PMRQ are ...
... perpendicular to the upper surface of the prism . Join OM , RP , SQ intersecting each other in N. Then it is easy to see that MN = NO and consequently _SO = QN , and as the triangles POR , PMR are equal , the pyramids PSRO and PMRQ are ...
Сторінка 120
... perpendicular to both the lines ( 1 ) and ( 2 ) , since we have - 1 ( mn ' — n ' n ) + m ( n l ′ − n ' l ) + n ( lm ' — l′m ) = 0 , - and l ' ( mn ' - m'n ) + m ' ( nl ' — n ' l ) + n ' ( lm ' − l ′ m ) = 0 , - which are the ...
... perpendicular to both the lines ( 1 ) and ( 2 ) , since we have - 1 ( mn ' — n ' n ) + m ( n l ′ − n ' l ) + n ( lm ' — l′m ) = 0 , - and l ' ( mn ' - m'n ) + m ' ( nl ' — n ' l ) + n ' ( lm ' − l ′ m ) = 0 , - which are the ...
Сторінка 126
... perpendicular to AB , and let AN = x , ON = y ; also let AON = 0 , BON = 4 , CON = y . Then u2 = x2 + y3 , v2 = ( c − x ) 2 + y2 , w2 = ( b cos A − x ) 2 + ( b sin A − y ) 2 . In order that u + v + w may be a minimum , we must have ...
... perpendicular to AB , and let AN = x , ON = y ; also let AON = 0 , BON = 4 , CON = y . Then u2 = x2 + y3 , v2 = ( c − x ) 2 + y2 , w2 = ( b cos A − x ) 2 + ( b sin A − y ) 2 . In order that u + v + w may be a minimum , we must have ...
Сторінка 130
... perpendicular CDE , of indefinite length . Take a point O in CA produced such that 40AC ; then if the reetangular ruler NLM , of which the leg LM is equal to the diameter of the circle , be moved so that the leg NL always slides along O ...
... perpendicular CDE , of indefinite length . Take a point O in CA produced such that 40AC ; then if the reetangular ruler NLM , of which the leg LM is equal to the diameter of the circle , be moved so that the leg NL always slides along O ...
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